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1(x-3)=5+2(2x-5)2123
We move all terms to the left:
1(x-3)-(5+2(2x-5)2123)=0
We calculate terms in parentheses: -(5+2(2x-5)2123), so:We get rid of parentheses
5+2(2x-5)2123
determiningTheFunctionDomain 2(2x-5)2123+5
We multiply parentheses
8492x-21230+5
We add all the numbers together, and all the variables
8492x-21225
Back to the equation:
-(8492x-21225)
1(x-3)-8492x+21225=0
We add all the numbers together, and all the variables
-8492x+1(x-3)+21225=0
We move all terms containing x to the left, all other terms to the right
-8492x+1(x-3)=-21225
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