1(x-4)+4=-7(x-3)

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Solution for 1(x-4)+4=-7(x-3) equation: 



1(x-4)+4=-7(x-3)

We move all terms to the left:

1(x-4)+4-(-7(x-3))=0



We calculate terms in parentheses: -(-7(x-3)), so:

-7(x-3)

We multiply parentheses

-7x+21

Back to the equation:

-(-7x+21)



We get rid of parentheses

1(x-4)+7x-21+4=0

We add all the numbers together, and all the variables

7x+1(x-4)-17=0

We move all terms containing x to the left, all other terms to the right

7x+1(x-4)=17

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