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1(x-5)+6=2(x+5)
We move all terms to the left:
1(x-5)+6-(2(x+5))=0
We calculate terms in parentheses: -(2(x+5)), so:We get rid of parentheses
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
1(x-5)-2x-10+6=0
We add all the numbers together, and all the variables
-2x+1(x-5)-4=0
We move all terms containing x to the left, all other terms to the right
-2x+1(x-5)=4
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