1(x-5)+7x=4(2x+3)-10

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Solution for 1(x-5)+7x=4(2x+3)-10 equation:


Simplifying
1(x + -5) + 7x = 4(2x + 3) + -10

Reorder the terms:
1(-5 + x) + 7x = 4(2x + 3) + -10
(-5 * 1 + x * 1) + 7x = 4(2x + 3) + -10
(-5 + 1x) + 7x = 4(2x + 3) + -10

Combine like terms: 1x + 7x = 8x
-5 + 8x = 4(2x + 3) + -10

Reorder the terms:
-5 + 8x = 4(3 + 2x) + -10
-5 + 8x = (3 * 4 + 2x * 4) + -10
-5 + 8x = (12 + 8x) + -10

Reorder the terms:
-5 + 8x = 12 + -10 + 8x

Combine like terms: 12 + -10 = 2
-5 + 8x = 2 + 8x

Add '-8x' to each side of the equation.
-5 + 8x + -8x = 2 + 8x + -8x

Combine like terms: 8x + -8x = 0
-5 + 0 = 2 + 8x + -8x
-5 = 2 + 8x + -8x

Combine like terms: 8x + -8x = 0
-5 = 2 + 0
-5 = 2

Solving
-5 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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