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1(x-8)+3=5(x+7)
We move all terms to the left:
1(x-8)+3-(5(x+7))=0
We calculate terms in parentheses: -(5(x+7)), so:We get rid of parentheses
5(x+7)
We multiply parentheses
5x+35
Back to the equation:
-(5x+35)
1(x-8)-5x-35+3=0
We add all the numbers together, and all the variables
-5x+1(x-8)-32=0
We move all terms containing x to the left, all other terms to the right
-5x+1(x-8)=32
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