1(y+2)(y-2)=0

Solution for 1(y+2)(y-2)=0 equation:

Simplifying
1(y + 2)(y + -2) = 0

Reorder the terms:
1(2 + y)(y + -2) = 0

Reorder the terms:
1(2 + y)(-2 + y) = 0

Multiply (2 + y) * (-2 + y)
1(2(-2 + y) + y(-2 + y)) = 0
1((-2 * 2 + y * 2) + y(-2 + y)) = 0
1((-4 + 2y) + y(-2 + y)) = 0
1(-4 + 2y + (-2 * y + y * y)) = 0
1(-4 + 2y + (-2y + y2)) = 0

Combine like terms: 2y + -2y = 0
1(-4 + 0 + y2) = 0
1(-4 + y2) = 0
(-4 * 1 + y2 * 1) = 0
(-4 + 1y2) = 0

Solving
-4 + 1y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 1y2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 1y2 = 0 + 4
1y2 = 0 + 4

Combine like terms: 0 + 4 = 4
1y2 = 4

Divide each side by '1'.
y2 = 4

Simplifying
y2 = 4

Take the square root of each side:
y = {-2, 2}