1(y+3)=2(y+-4)=-7

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Solution for 1(y+3)=2(y+-4)=-7 equation: 



1(y+3)=2(y+-4)=-7

We move all terms to the left:

1(y+3)-(2(y+-4))=0

We add all the numbers together, and all the variables

1(y+3)-(2(y-4))=0



We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We get rid of parentheses

1(y+3)-2y+8=0

We add all the numbers together, and all the variables

-2y+1(y+3)+8=0

We move all terms containing y to the left, all other terms to the right

-2y+1(y+3)=-8

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