1(y+3)=2y-1

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Solution for 1(y+3)=2y-1 equation: 



1(y+3)=2y-1

We move all terms to the left:

1(y+3)-(2y-1)=0

We get rid of parentheses

1(y+3)-2y+1=0

We add all the numbers together, and all the variables

-2y+1(y+3)+1=0

We move all terms containing y to the left, all other terms to the right

-2y+1(y+3)=-1

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