1(z+8)(z-8)=

Solution for 1(z+8)(z-8)= equation:

Simplifying
1(z + 8)(z + -8) = 0

Reorder the terms:
1(8 + z)(z + -8) = 0

Reorder the terms:
1(8 + z)(-8 + z) = 0

Multiply (8 + z) * (-8 + z)
1(8(-8 + z) + z(-8 + z)) = 0
1((-8 * 8 + z * 8) + z(-8 + z)) = 0
1((-64 + 8z) + z(-8 + z)) = 0
1(-64 + 8z + (-8 * z + z * z)) = 0
1(-64 + 8z + (-8z + z2)) = 0

Combine like terms: 8z + -8z = 0
1(-64 + 0 + z2) = 0
1(-64 + z2) = 0
(-64 * 1 + z2 * 1) = 0
(-64 + 1z2) = 0

Solving
-64 + 1z2 = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '64' to each side of the equation.
-64 + 64 + 1z2 = 0 + 64

Combine like terms: -64 + 64 = 0
0 + 1z2 = 0 + 64
1z2 = 0 + 64

Combine like terms: 0 + 64 = 64
1z2 = 64

Divide each side by '1'.
z2 = 64

Simplifying
z2 = 64

Take the square root of each side:
z = {-8, 8}