1)3(b-5=4b-19

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Solution for 1)3(b-5=4b-19 equation: 



1)3(b-5=4b-19

We move all terms to the left:

1)3(b-5-(4b-19)=0

We get rid of parentheses

1)3(b-4b+19-5=0

We add all the numbers together, and all the variables

-4b+1)3(b+14=0

We move all terms containing b to the left, all other terms to the right

-4b+1)3(b=-14

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