1+((x-2)/2)=3x

Solution for 1+((x-2)/2)=3x equation:

1+((x-2)/2)=3x

We move all terms to the left:

1+((x-2)/2)-(3x)=0

We add all the numbers together, and all the variables

-3x+((x-2)/2)+1=0

We multiply all the terms by the denominator


-3x*2)+((x-2)+1*2)=0

We add all the numbers together, and all the variables

-3x*2)+((x-2)=0

Wy multiply elements

-6x^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-12}=0$