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1+(3/4)s=2/3
We move all terms to the left:
1+(3/4)s-(2/3)=0
Domain of the equation: 4)s!=0We add all the numbers together, and all the variables
s!=0/1
s!=0
s∈R
(+3/4)s+1-(+2/3)=0
We multiply parentheses
3s^2+1-(+2/3)=0
We get rid of parentheses
3s^2+1-2/3=0
We multiply all the terms by the denominator
3s^2*3-2+1*3=0
We add all the numbers together, and all the variables
3s^2*3+1=0
Wy multiply elements
9s^2+1=0
a = 9; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·9·1
Δ = -36
Delta is less than zero, so there is no solution for the equation
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