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1+(5/3x)=7/3x
We move all terms to the left:
1+(5/3x)-(7/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+5/3x)-(+7/3x)+1=0
We get rid of parentheses
5/3x-7/3x+1=0
We multiply all the terms by the denominator
1*3x+5-7=0
We add all the numbers together, and all the variables
1*3x-2=0
Wy multiply elements
3x-2=0
We move all terms containing x to the left, all other terms to the right
3x=2
x=2/3
x=2/3
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