1+(7c-3)=7(-3c+5)+2

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Solution for 1+(7c-3)=7(-3c+5)+2 equation: 



1+(7c-3)=7(-3c+5)+2

We move all terms to the left:

1+(7c-3)-(7(-3c+5)+2)=0

We get rid of parentheses

7c-(7(-3c+5)+2)-3+1=0



We calculate terms in parentheses: -(7(-3c+5)+2), so:

7(-3c+5)+2

We multiply parentheses

-21c+35+2

We add all the numbers together, and all the variables

-21c+37

Back to the equation:

-(-21c+37)



We add all the numbers together, and all the variables

7c-(-21c+37)-2=0

We get rid of parentheses

7c+21c-37-2=0

We add all the numbers together, and all the variables

28c-39=0

We move all terms containing c to the left, all other terms to the right

28c=39

c=39/28

c=1+11/28

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