1+(7z-3)=7(-3+5)+2

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Solution for 1+(7z-3)=7(-3+5)+2 equation:


Simplifying
1 + (7z + -3) = 7(-3 + 5) + 2

Reorder the terms:
1 + (-3 + 7z) = 7(-3 + 5) + 2

Remove parenthesis around (-3 + 7z)
1 + -3 + 7z = 7(-3 + 5) + 2

Combine like terms: 1 + -3 = -2
-2 + 7z = 7(-3 + 5) + 2

Combine like terms: -3 + 5 = 2
-2 + 7z = 7(2) + 2

Multiply 7 * 2
-2 + 7z = 14 + 2

Combine like terms: 14 + 2 = 16
-2 + 7z = 16

Solving
-2 + 7z = 16

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 7z = 16 + 2

Combine like terms: -2 + 2 = 0
0 + 7z = 16 + 2
7z = 16 + 2

Combine like terms: 16 + 2 = 18
7z = 18

Divide each side by '7'.
z = 2.571428571

Simplifying
z = 2.571428571

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