1+(7z-3)=7(-3x+5)+2

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Solution for 1+(7z-3)=7(-3x+5)+2 equation:


Simplifying
1 + (7z + -3) = 7(-3x + 5) + 2

Reorder the terms:
1 + (-3 + 7z) = 7(-3x + 5) + 2

Remove parenthesis around (-3 + 7z)
1 + -3 + 7z = 7(-3x + 5) + 2

Combine like terms: 1 + -3 = -2
-2 + 7z = 7(-3x + 5) + 2

Reorder the terms:
-2 + 7z = 7(5 + -3x) + 2
-2 + 7z = (5 * 7 + -3x * 7) + 2
-2 + 7z = (35 + -21x) + 2

Reorder the terms:
-2 + 7z = 35 + 2 + -21x

Combine like terms: 35 + 2 = 37
-2 + 7z = 37 + -21x

Solving
-2 + 7z = 37 + -21x

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 7z = 37 + 2 + -21x

Combine like terms: -2 + 2 = 0
0 + 7z = 37 + 2 + -21x
7z = 37 + 2 + -21x

Combine like terms: 37 + 2 = 39
7z = 39 + -21x

Divide each side by '7'.
z = 5.571428571 + -3x

Simplifying
z = 5.571428571 + -3x

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