1+(7z-3)=7(-3z+5)+2

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Solution for 1+(7z-3)=7(-3z+5)+2 equation:


Simplifying
1 + (7z + -3) = 7(-3z + 5) + 2

Reorder the terms:
1 + (-3 + 7z) = 7(-3z + 5) + 2

Remove parenthesis around (-3 + 7z)
1 + -3 + 7z = 7(-3z + 5) + 2

Combine like terms: 1 + -3 = -2
-2 + 7z = 7(-3z + 5) + 2

Reorder the terms:
-2 + 7z = 7(5 + -3z) + 2
-2 + 7z = (5 * 7 + -3z * 7) + 2
-2 + 7z = (35 + -21z) + 2

Reorder the terms:
-2 + 7z = 35 + 2 + -21z

Combine like terms: 35 + 2 = 37
-2 + 7z = 37 + -21z

Solving
-2 + 7z = 37 + -21z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '21z' to each side of the equation.
-2 + 7z + 21z = 37 + -21z + 21z

Combine like terms: 7z + 21z = 28z
-2 + 28z = 37 + -21z + 21z

Combine like terms: -21z + 21z = 0
-2 + 28z = 37 + 0
-2 + 28z = 37

Add '2' to each side of the equation.
-2 + 2 + 28z = 37 + 2

Combine like terms: -2 + 2 = 0
0 + 28z = 37 + 2
28z = 37 + 2

Combine like terms: 37 + 2 = 39
28z = 39

Divide each side by '28'.
z = 1.392857143

Simplifying
z = 1.392857143

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