1+(b-40)=4/3

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Solution for 1+(b-40)=4/3 equation: 



1+(b-40)=4/3

We move all terms to the left:

1+(b-40)-(4/3)=0

We add all the numbers together, and all the variables

(b-40)+1-(+4/3)=0

We get rid of parentheses

b-40+1-4/3=0

We multiply all the terms by the denominator


b*3-4-40*3+1*3=0

We add all the numbers together, and all the variables

b*3-121=0

Wy multiply elements

3b-121=0

We move all terms containing b to the left, all other terms to the right

3b=121

b=121/3

b=40+1/3

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