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1+1/2(-x+5)=2+3(1-x)
We move all terms to the left:
1+1/2(-x+5)-(2+3(1-x))=0
Domain of the equation: 2(-x+5)!=0We add all the numbers together, and all the variables
x∈R
1/2(-1x+5)-(2+3(-1x+1))+1=0
We multiply all the terms by the denominator
-((2+3(-1x+1)))*2(-1x+5)+1*2(-1x+5)+1=0
We calculate terms in parentheses: -((2+3(-1x+1)))*2(-1x+5), so:We add all the numbers together, and all the variables
(2+3(-1x+1)))*2(-1x+5
We add all the numbers together, and all the variables
-1x+(2+3(-1x+1)))*2(+5
Back to the equation:
-(-1x+(2+3(-1x+1)))*2(+5)
-(-1x+(2+3(-1x+1)))*25+1*2(-1x+5)+1=0
Wy multiply elements
-(-1x+(2+3(-1x+1)))*25+2x(-+1=0
We use the square of the difference formula
-(-1x+(2+3(-1x+1)))*25+2x(-1=0
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