1+1/2(4x+2)=2(x+1)

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Solution for 1+1/2(4x+2)=2(x+1) equation:



1+1/2(4x+2)=2(x+1)
We move all terms to the left:
1+1/2(4x+2)-(2(x+1))=0
Domain of the equation: 2(4x+2)!=0
x∈R
We multiply all the terms by the denominator
-((2(x+1)))*2(4x+2)+1*2(4x+2)+1=0
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
Wy multiply elements
-((2(x+1)))*2(4x+2)+2x(4+1=0
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2
We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:
(2(x+1)))*2(4x+2

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