1+1/2(4x+2)=2(x+1)

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Solution for 1+1/2(4x+2)=2(x+1) equation: 



1+1/2(4x+2)=2(x+1)

We move all terms to the left:

1+1/2(4x+2)-(2(x+1))=0



Domain of the equation: 2(4x+2)!=0

x∈R



We multiply all the terms by the denominator


-((2(x+1)))*2(4x+2)+1*2(4x+2)+1=0



We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2



Wy multiply elements

-((2(x+1)))*2(4x+2)+2x(4+1=0



We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





We calculate terms in parentheses: -((2(x+1)))*2(4x+2), so:

(2(x+1)))*2(4x+2





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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