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1+1/9x=1/11x
We move all terms to the left:
1+1/9x-(1/11x)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 11x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/9x-(+1/11x)+1=0
We get rid of parentheses
1/9x-1/11x+1=0
We calculate fractions
11x/99x^2+(-9x)/99x^2+1=0
We multiply all the terms by the denominator
11x+(-9x)+1*99x^2=0
Wy multiply elements
99x^2+11x+(-9x)=0
We get rid of parentheses
99x^2+11x-9x=0
We add all the numbers together, and all the variables
99x^2+2x=0
a = 99; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·99·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*99}=\frac{-4}{198} =-2/99 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*99}=\frac{0}{198} =0 $
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