1+10(q-3)=-20-(9-4q)

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Solution for 1+10(q-3)=-20-(9-4q) equation:


Simplifying
1 + 10(q + -3) = -20 + -1(9 + -4q)

Reorder the terms:
1 + 10(-3 + q) = -20 + -1(9 + -4q)
1 + (-3 * 10 + q * 10) = -20 + -1(9 + -4q)
1 + (-30 + 10q) = -20 + -1(9 + -4q)

Combine like terms: 1 + -30 = -29
-29 + 10q = -20 + -1(9 + -4q)
-29 + 10q = -20 + (9 * -1 + -4q * -1)
-29 + 10q = -20 + (-9 + 4q)

Combine like terms: -20 + -9 = -29
-29 + 10q = -29 + 4q

Add '29' to each side of the equation.
-29 + 29 + 10q = -29 + 29 + 4q

Combine like terms: -29 + 29 = 0
0 + 10q = -29 + 29 + 4q
10q = -29 + 29 + 4q

Combine like terms: -29 + 29 = 0
10q = 0 + 4q
10q = 4q

Solving
10q = 4q

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-4q' to each side of the equation.
10q + -4q = 4q + -4q

Combine like terms: 10q + -4q = 6q
6q = 4q + -4q

Combine like terms: 4q + -4q = 0
6q = 0

Divide each side by '6'.
q = 0

Simplifying
q = 0

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