1+10n-11n=-(12-5)+7(2n-4)

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Solution for 1+10n-11n=-(12-5)+7(2n-4) equation: 



1+10n-11n=-(12-5)+7(2n-4)

We move all terms to the left:

1+10n-11n-(-(12-5)+7(2n-4))=0

We add all the numbers together, and all the variables

10n-11n-(-7+7(2n-4))+1=0

We add all the numbers together, and all the variables

-1n-(-7+7(2n-4))+1=0



We calculate terms in parentheses: -(-7+7(2n-4)), so:

-7+7(2n-4)

determiningTheFunctionDomain
7(2n-4)-7

We multiply parentheses

14n-28-7

We add all the numbers together, and all the variables

14n-35

Back to the equation:

-(14n-35)



We get rid of parentheses

-1n-14n+35+1=0

We add all the numbers together, and all the variables

-15n+36=0

We move all terms containing n to the left, all other terms to the right

-15n=-36

n=-36/-15

n=2+2/5

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