1+1a=(3a+4)/9

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Solution for 1+1a=(3a+4)/9 equation: 



1+1a=(3a+4)/9

We move all terms to the left:

1+1a-((3a+4)/9)=0

We add all the numbers together, and all the variables

a-((3a+4)/9)+1=0

We multiply all the terms by the denominator


a*9)-((3a+4)+1*9)=0

We add all the numbers together, and all the variables

a*9)-((3a+4)=0

Wy multiply elements

9a^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{18}=0$

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