1+2(1b+6)=5(1b-1)

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Solution for 1+2(1b+6)=5(1b-1) equation:


Simplifying
1 + 2(1b + 6) = 5(1b + -1)

Reorder the terms:
1 + 2(6 + 1b) = 5(1b + -1)
1 + (6 * 2 + 1b * 2) = 5(1b + -1)
1 + (12 + 2b) = 5(1b + -1)

Combine like terms: 1 + 12 = 13
13 + 2b = 5(1b + -1)

Reorder the terms:
13 + 2b = 5(-1 + 1b)
13 + 2b = (-1 * 5 + 1b * 5)
13 + 2b = (-5 + 5b)

Solving
13 + 2b = -5 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
13 + 2b + -5b = -5 + 5b + -5b

Combine like terms: 2b + -5b = -3b
13 + -3b = -5 + 5b + -5b

Combine like terms: 5b + -5b = 0
13 + -3b = -5 + 0
13 + -3b = -5

Add '-13' to each side of the equation.
13 + -13 + -3b = -5 + -13

Combine like terms: 13 + -13 = 0
0 + -3b = -5 + -13
-3b = -5 + -13

Combine like terms: -5 + -13 = -18
-3b = -18

Divide each side by '-3'.
b = 6

Simplifying
b = 6

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