1+2(3X+2)=5(2x-3)

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Solution for 1+2(3X+2)=5(2x-3) equation: 



1+2(3X+2)=5(2X-3)

We move all terms to the left:

1+2(3X+2)-(5(2X-3))=0

We multiply parentheses

6X-(5(2X-3))+4+1=0



We calculate terms in parentheses: -(5(2X-3)), so:

5(2X-3)

We multiply parentheses

10X-15

Back to the equation:

-(10X-15)



We add all the numbers together, and all the variables

6X-(10X-15)+5=0

We get rid of parentheses

6X-10X+15+5=0

We add all the numbers together, and all the variables

-4X+20=0

We move all terms containing X to the left, all other terms to the right

-4X=-20

X=-20/-4

X=+5

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