1+2(3c+4)=6c-9(c+7)

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Solution for 1+2(3c+4)=6c-9(c+7) equation: 



1+2(3c+4)=6c-9(c+7)

We move all terms to the left:

1+2(3c+4)-(6c-9(c+7))=0

We multiply parentheses

6c-(6c-9(c+7))+8+1=0



We calculate terms in parentheses: -(6c-9(c+7)), so:

6c-9(c+7)

We multiply parentheses

6c-9c-63

We add all the numbers together, and all the variables

-3c-63

Back to the equation:

-(-3c-63)



We add all the numbers together, and all the variables

6c-(-3c-63)+9=0

We get rid of parentheses

6c+3c+63+9=0

We add all the numbers together, and all the variables

9c+72=0

We move all terms containing c to the left, all other terms to the right

9c=-72

c=-72/9

c=-8

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