1+2(4w-4)-3w=5(w-2)+3

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Solution for 1+2(4w-4)-3w=5(w-2)+3 equation:


Simplifying
1 + 2(4w + -4) + -3w = 5(w + -2) + 3

Reorder the terms:
1 + 2(-4 + 4w) + -3w = 5(w + -2) + 3
1 + (-4 * 2 + 4w * 2) + -3w = 5(w + -2) + 3
1 + (-8 + 8w) + -3w = 5(w + -2) + 3

Combine like terms: 1 + -8 = -7
-7 + 8w + -3w = 5(w + -2) + 3

Combine like terms: 8w + -3w = 5w
-7 + 5w = 5(w + -2) + 3

Reorder the terms:
-7 + 5w = 5(-2 + w) + 3
-7 + 5w = (-2 * 5 + w * 5) + 3
-7 + 5w = (-10 + 5w) + 3

Reorder the terms:
-7 + 5w = -10 + 3 + 5w

Combine like terms: -10 + 3 = -7
-7 + 5w = -7 + 5w

Add '7' to each side of the equation.
-7 + 7 + 5w = -7 + 7 + 5w

Combine like terms: -7 + 7 = 0
0 + 5w = -7 + 7 + 5w
5w = -7 + 7 + 5w

Combine like terms: -7 + 7 = 0
5w = 0 + 5w
5w = 5w

Add '-5w' to each side of the equation.
5w + -5w = 5w + -5w

Combine like terms: 5w + -5w = 0
0 = 5w + -5w

Combine like terms: 5w + -5w = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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