1+2(b-6)=5(b-1)

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Solution for 1+2(b-6)=5(b-1) equation: 



1+2(b-6)=5(b-1)

We move all terms to the left:

1+2(b-6)-(5(b-1))=0

We multiply parentheses

2b-(5(b-1))-12+1=0



We calculate terms in parentheses: -(5(b-1)), so:

5(b-1)

We multiply parentheses

5b-5

Back to the equation:

-(5b-5)



We add all the numbers together, and all the variables

2b-(5b-5)-11=0

We get rid of parentheses

2b-5b+5-11=0

We add all the numbers together, and all the variables

-3b-6=0

We move all terms containing b to the left, all other terms to the right

-3b=6

b=6/-3

b=-2

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