1+2(d+1)=3+4(3+5)

Solution for 1+2(d+1)=3+4(3+5) equation:

Simplifying
1 + 2(d + 1) = 3 + 4(3 + 5)

Reorder the terms:
1 + 2(1 + d) = 3 + 4(3 + 5)
1 + (1 * 2 + d * 2) = 3 + 4(3 + 5)
1 + (2 + 2d) = 3 + 4(3 + 5)

Combine like terms: 1 + 2 = 3
3 + 2d = 3 + 4(3 + 5)

Combine like terms: 3 + 5 = 8
3 + 2d = 3 + 4(8)

Multiply 4 * 8
3 + 2d = 3 + 32

Combine like terms: 3 + 32 = 35
3 + 2d = 35

Solving
3 + 2d = 35

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2d = 35 + -3

Combine like terms: 3 + -3 = 0
0 + 2d = 35 + -3
2d = 35 + -3

Combine like terms: 35 + -3 = 32
2d = 32

Divide each side by '2'.
d = 16

Simplifying
d = 16