1+2(d+1)=3+4(d+5)

Solution for 1+2(d+1)=3+4(d+5) equation:

Simplifying
1 + 2(d + 1) = 3 + 4(d + 5)

Reorder the terms:
1 + 2(1 + d) = 3 + 4(d + 5)
1 + (1 * 2 + d * 2) = 3 + 4(d + 5)
1 + (2 + 2d) = 3 + 4(d + 5)

Combine like terms: 1 + 2 = 3
3 + 2d = 3 + 4(d + 5)

Reorder the terms:
3 + 2d = 3 + 4(5 + d)
3 + 2d = 3 + (5 * 4 + d * 4)
3 + 2d = 3 + (20 + 4d)

Combine like terms: 3 + 20 = 23
3 + 2d = 23 + 4d

Solving
3 + 2d = 23 + 4d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4d' to each side of the equation.
3 + 2d + -4d = 23 + 4d + -4d

Combine like terms: 2d + -4d = -2d
3 + -2d = 23 + 4d + -4d

Combine like terms: 4d + -4d = 0
3 + -2d = 23 + 0
3 + -2d = 23

Add '-3' to each side of the equation.
3 + -3 + -2d = 23 + -3

Combine like terms: 3 + -3 = 0
0 + -2d = 23 + -3
-2d = 23 + -3

Combine like terms: 23 + -3 = 20
-2d = 20

Divide each side by '-2'.
d = -10

Simplifying
d = -10