1+2(d+1)=3+8(b+9)

Solution for 1+2(d+1)=3+8(b+9) equation:

Simplifying
1 + 2(d + 1) = 3 + 8(b + 9)

Reorder the terms:
1 + 2(1 + d) = 3 + 8(b + 9)
1 + (1 * 2 + d * 2) = 3 + 8(b + 9)
1 + (2 + 2d) = 3 + 8(b + 9)

Combine like terms: 1 + 2 = 3
3 + 2d = 3 + 8(b + 9)

Reorder the terms:
3 + 2d = 3 + 8(9 + b)
3 + 2d = 3 + (9 * 8 + b * 8)
3 + 2d = 3 + (72 + 8b)

Combine like terms: 3 + 72 = 75
3 + 2d = 75 + 8b

Solving
3 + 2d = 75 + 8b

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2d = 75 + -3 + 8b

Combine like terms: 3 + -3 = 0
0 + 2d = 75 + -3 + 8b
2d = 75 + -3 + 8b

Combine like terms: 75 + -3 = 72
2d = 72 + 8b

Divide each side by '2'.
d = 36 + 4b

Simplifying
d = 36 + 4b