1+2(h+6)=5(b-1)

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Solution for 1+2(h+6)=5(b-1) equation:


Simplifying
1 + 2(h + 6) = 5(b + -1)

Reorder the terms:
1 + 2(6 + h) = 5(b + -1)
1 + (6 * 2 + h * 2) = 5(b + -1)
1 + (12 + 2h) = 5(b + -1)

Combine like terms: 1 + 12 = 13
13 + 2h = 5(b + -1)

Reorder the terms:
13 + 2h = 5(-1 + b)
13 + 2h = (-1 * 5 + b * 5)
13 + 2h = (-5 + 5b)

Solving
13 + 2h = -5 + 5b

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 2h = -5 + -13 + 5b

Combine like terms: 13 + -13 = 0
0 + 2h = -5 + -13 + 5b
2h = -5 + -13 + 5b

Combine like terms: -5 + -13 = -18
2h = -18 + 5b

Divide each side by '2'.
h = -9 + 2.5b

Simplifying
h = -9 + 2.5b

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