1+2(x+1)=3+4(x+5)

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Solution for 1+2(x+1)=3+4(x+5) equation: 



1+2(x+1)=3+4(x+5)

We move all terms to the left:

1+2(x+1)-(3+4(x+5))=0

We multiply parentheses

2x-(3+4(x+5))+2+1=0



We calculate terms in parentheses: -(3+4(x+5)), so:

3+4(x+5)

determiningTheFunctionDomain
4(x+5)+3

We multiply parentheses

4x+20+3

We add all the numbers together, and all the variables

4x+23

Back to the equation:

-(4x+23)



We add all the numbers together, and all the variables

2x-(4x+23)+3=0

We get rid of parentheses

2x-4x-23+3=0

We add all the numbers together, and all the variables

-2x-20=0

We move all terms containing x to the left, all other terms to the right

-2x=20

x=20/-2

x=-10

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