1+2(x+5)=x+3(x-1)

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Solution for 1+2(x+5)=x+3(x-1) equation: 



1+2(x+5)=x+3(x-1)

We move all terms to the left:

1+2(x+5)-(x+3(x-1))=0

We multiply parentheses

2x-(x+3(x-1))+10+1=0



We calculate terms in parentheses: -(x+3(x-1)), so:

x+3(x-1)

We multiply parentheses

x+3x-3

We add all the numbers together, and all the variables

4x-3

Back to the equation:

-(4x-3)



We add all the numbers together, and all the variables

2x-(4x-3)+11=0

We get rid of parentheses

2x-4x+3+11=0

We add all the numbers together, and all the variables

-2x+14=0

We move all terms containing x to the left, all other terms to the right

-2x=-14

x=-14/-2

x=+7

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