1+2(x-3)=3(x+1)

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Solution for 1+2(x-3)=3(x+1) equation: 



1+2(x-3)=3(x+1)

We move all terms to the left:

1+2(x-3)-(3(x+1))=0

We multiply parentheses

2x-(3(x+1))-6+1=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

2x-(3x+3)-5=0

We get rid of parentheses

2x-3x-3-5=0

We add all the numbers together, and all the variables

-1x-8=0

We move all terms containing x to the left, all other terms to the right

-x=8

x=8/-1

x=-8

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