1+2(x-3)=3(x+1)

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Solution for 1+2(x-3)=3(x+1) equation:



1+2(x-3)=3(x+1)
We move all terms to the left:
1+2(x-3)-(3(x+1))=0
We multiply parentheses
2x-(3(x+1))-6+1=0
We calculate terms in parentheses: -(3(x+1)), so:
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
We add all the numbers together, and all the variables
2x-(3x+3)-5=0
We get rid of parentheses
2x-3x-3-5=0
We add all the numbers together, and all the variables
-1x-8=0
We move all terms containing x to the left, all other terms to the right
-x=8
x=8/-1
x=-8

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