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1+2/3(6x-12)=3
We move all terms to the left:
1+2/3(6x-12)-(3)=0
Domain of the equation: 3(6x-12)!=0We add all the numbers together, and all the variables
x∈R
2/3(6x-12)-2=0
We multiply all the terms by the denominator
-2*3(6x-12)+2=0
Wy multiply elements
-6x(6+2=0
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