1+25-(3x-2)=3

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Solution for 1+25-(3x-2)=3 equation: 



1+25-(3x-2)=3

We move all terms to the left:

1+25-(3x-2)-(3)=0

We add all the numbers together, and all the variables

-(3x-2)+23=0

We get rid of parentheses

-3x+2+23=0

We add all the numbers together, and all the variables

-3x+25=0

We move all terms containing x to the left, all other terms to the right

-3x=-25

x=-25/-3

x=8+1/3

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