1+2i+i(x+iy)=y+i(3x)

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Solution for 1+2i+i(x+iy)=y+i(3x) equation:


Simplifying
1 + 2i + i(x + iy) = y + i(3x)

Reorder the terms:
1 + 2i + i(iy + x) = y + i(3x)
1 + 2i + (iy * i + x * i) = y + i(3x)

Reorder the terms:
1 + 2i + (ix + i2y) = y + i(3x)
1 + 2i + (ix + i2y) = y + i(3x)

Remove parenthesis around (3x)
1 + 2i + ix + i2y = y + i * 3x

Reorder the terms for easier multiplication:
1 + 2i + ix + i2y = y + 3i * x

Multiply i * x
1 + 2i + ix + i2y = y + 3ix

Reorder the terms:
1 + 2i + ix + i2y = 3ix + y

Solving
1 + 2i + ix + i2y = 3ix + y

Solving for variable 'i'.

Reorder the terms:
1 + 2i + ix + -3ix + i2y + -1y = 3ix + y + -3ix + -1y

Combine like terms: ix + -3ix = -2ix
1 + 2i + -2ix + i2y + -1y = 3ix + y + -3ix + -1y

Reorder the terms:
1 + 2i + -2ix + i2y + -1y = 3ix + -3ix + y + -1y

Combine like terms: 3ix + -3ix = 0
1 + 2i + -2ix + i2y + -1y = 0 + y + -1y
1 + 2i + -2ix + i2y + -1y = y + -1y

Combine like terms: y + -1y = 0
1 + 2i + -2ix + i2y + -1y = 0

The solution to this equation could not be determined.

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