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Simplifying 1 + 2i + i(x + iy) = y + i(3x) Reorder the terms: 1 + 2i + i(iy + x) = y + i(3x) 1 + 2i + (iy * i + x * i) = y + i(3x) Reorder the terms: 1 + 2i + (ix + i2y) = y + i(3x) 1 + 2i + (ix + i2y) = y + i(3x) Remove parenthesis around (3x) 1 + 2i + ix + i2y = y + i * 3x Reorder the terms for easier multiplication: 1 + 2i + ix + i2y = y + 3i * x Multiply i * x 1 + 2i + ix + i2y = y + 3ix Reorder the terms: 1 + 2i + ix + i2y = 3ix + y Solving 1 + 2i + ix + i2y = 3ix + y Solving for variable 'i'. Reorder the terms: 1 + 2i + ix + -3ix + i2y + -1y = 3ix + y + -3ix + -1y Combine like terms: ix + -3ix = -2ix 1 + 2i + -2ix + i2y + -1y = 3ix + y + -3ix + -1y Reorder the terms: 1 + 2i + -2ix + i2y + -1y = 3ix + -3ix + y + -1y Combine like terms: 3ix + -3ix = 0 1 + 2i + -2ix + i2y + -1y = 0 + y + -1y 1 + 2i + -2ix + i2y + -1y = y + -1y Combine like terms: y + -1y = 0 1 + 2i + -2ix + i2y + -1y = 0 The solution to this equation could not be determined.
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