1+2m=7-6(1+5m)

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Solution for 1+2m=7-6(1+5m) equation: 



1+2m=7-6(1+5m)

We move all terms to the left:

1+2m-(7-6(1+5m))=0

We add all the numbers together, and all the variables

2m-(7-6(5m+1))+1=0



We calculate terms in parentheses: -(7-6(5m+1)), so:

7-6(5m+1)

determiningTheFunctionDomain
-6(5m+1)+7

We multiply parentheses

-30m-6+7

We add all the numbers together, and all the variables

-30m+1

Back to the equation:

-(-30m+1)



We get rid of parentheses

2m+30m-1+1=0

We add all the numbers together, and all the variables

32m=0

m=0/32

m=0

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