1+2x+1-x=(x-6)-8(5+x)

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Solution for 1+2x+1-x=(x-6)-8(5+x) equation:



1+2x+1-x=(x-6)-8(5+x)
We move all terms to the left:
1+2x+1-x-((x-6)-8(5+x))=0
We add all the numbers together, and all the variables
2x-x-((x-6)-8(x+5))+1+1=0
We add all the numbers together, and all the variables
x-((x-6)-8(x+5))+2=0
We calculate terms in parentheses: -((x-6)-8(x+5)), so:
(x-6)-8(x+5)
We multiply parentheses
(x-6)-8x-40
We get rid of parentheses
x-8x-6-40
We add all the numbers together, and all the variables
-7x-46
Back to the equation:
-(-7x-46)
We get rid of parentheses
x+7x+46+2=0
We add all the numbers together, and all the variables
8x+48=0
We move all terms containing x to the left, all other terms to the right
8x=-48
x=-48/8
x=-6

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