1+2x+5/x=6

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Solution for 1+2x+5/x=6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+5/x+1 = 6 // - 6

2*x+5/x-6+1 = 0

2*x^1+5*x^-1-5*x^0 = 0

(2*x^2-5*x^1+5*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-5*x^1+5*x^0) = 0

x^1

2*x^2-5*x+5 = 0

2*x^2-5*x+5 = 0

DELTA = (-5)^2-(2*4*5)

DELTA = -15

DELTA < 0

x in { } 

x belongs to the empty set

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