1+2x=3(2x+4)-5(x-2)

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Solution for 1+2x=3(2x+4)-5(x-2) equation: 



1+2x=3(2x+4)-5(x-2)

We move all terms to the left:

1+2x-(3(2x+4)-5(x-2))=0



We calculate terms in parentheses: -(3(2x+4)-5(x-2)), so:

3(2x+4)-5(x-2)

We multiply parentheses

6x-5x+12+10

We add all the numbers together, and all the variables

x+22

Back to the equation:

-(x+22)



We get rid of parentheses

2x-x-22+1=0

We add all the numbers together, and all the variables

x-21=0

We move all terms containing x to the left, all other terms to the right

x=21

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