1+2x=3(x+2)-2(x-4)

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Solution for 1+2x=3(x+2)-2(x-4) equation: 



1+2x=3(x+2)-2(x-4)

We move all terms to the left:

1+2x-(3(x+2)-2(x-4))=0



We calculate terms in parentheses: -(3(x+2)-2(x-4)), so:

3(x+2)-2(x-4)

We multiply parentheses

3x-2x+6+8

We add all the numbers together, and all the variables

x+14

Back to the equation:

-(x+14)



We get rid of parentheses

2x-x-14+1=0

We add all the numbers together, and all the variables

x-13=0

We move all terms containing x to the left, all other terms to the right

x=13

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