1+2y+3=2(y+2)

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Solution for 1+2y+3=2(y+2) equation: 



1+2y+3=2(y+2)

We move all terms to the left:

1+2y+3-(2(y+2))=0

We add all the numbers together, and all the variables

2y-(2(y+2))+4=0



We calculate terms in parentheses: -(2(y+2)), so:

2(y+2)

We multiply parentheses

2y+4

Back to the equation:

-(2y+4)



We get rid of parentheses

2y-2y-4+4=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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