1+2y=(5+y)-(4-y)

Solution for 1+2y=(5+y)-(4-y) equation:

Simplifying
1 + 2y = (5 + y) + -1(4 + -1y)

Remove parenthesis around (5 + y)
1 + 2y = 5 + y + -1(4 + -1y)
1 + 2y = 5 + y + (4 * -1 + -1y * -1)
1 + 2y = 5 + y + (-4 + 1y)

Reorder the terms:
1 + 2y = 5 + -4 + y + 1y

Combine like terms: 5 + -4 = 1
1 + 2y = 1 + y + 1y

Combine like terms: y + 1y = 2y
1 + 2y = 1 + 2y

Add '-1' to each side of the equation.
1 + -1 + 2y = 1 + -1 + 2y

Combine like terms: 1 + -1 = 0
0 + 2y = 1 + -1 + 2y
2y = 1 + -1 + 2y

Combine like terms: 1 + -1 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.