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1+3(-x+1)=3(2x-2)+1
We move all terms to the left:
1+3(-x+1)-(3(2x-2)+1)=0
We add all the numbers together, and all the variables
3(-1x+1)-(3(2x-2)+1)+1=0
We multiply parentheses
-3x-(3(2x-2)+1)+3+1=0
We calculate terms in parentheses: -(3(2x-2)+1), so:We add all the numbers together, and all the variables
3(2x-2)+1
We multiply parentheses
6x-6+1
We add all the numbers together, and all the variables
6x-5
Back to the equation:
-(6x-5)
-3x-(6x-5)+4=0
We get rid of parentheses
-3x-6x+5+4=0
We add all the numbers together, and all the variables
-9x+9=0
We move all terms containing x to the left, all other terms to the right
-9x=-9
x=-9/-9
x=1
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