1+3(1-6r)=-7(7-5r)

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Solution for 1+3(1-6r)=-7(7-5r) equation: 



1+3(1-6r)=-7(7-5r)

We move all terms to the left:

1+3(1-6r)-(-7(7-5r))=0

We add all the numbers together, and all the variables

3(-6r+1)-(-7(-5r+7))+1=0

We multiply parentheses

-18r-(-7(-5r+7))+3+1=0



We calculate terms in parentheses: -(-7(-5r+7)), so:

-7(-5r+7)

We multiply parentheses

35r-49

Back to the equation:

-(35r-49)



We add all the numbers together, and all the variables

-18r-(35r-49)+4=0

We get rid of parentheses

-18r-35r+49+4=0

We add all the numbers together, and all the variables

-53r+53=0

We move all terms containing r to the left, all other terms to the right

-53r=-53

r=-53/-53

r=1

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