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1+3(2x+2)=6(x-1)
We move all terms to the left:
1+3(2x+2)-(6(x-1))=0
We multiply parentheses
6x-(6(x-1))+6+1=0
We calculate terms in parentheses: -(6(x-1)), so:We add all the numbers together, and all the variables
6(x-1)
We multiply parentheses
6x-6
Back to the equation:
-(6x-6)
6x-(6x-6)+7=0
We get rid of parentheses
6x-6x+6+7=0
We add all the numbers together, and all the variables
13!=0
There is no solution for this equation
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