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1+3(3+x)=6x-(x-6)
We move all terms to the left:
1+3(3+x)-(6x-(x-6))=0
We add all the numbers together, and all the variables
3(x+3)-(6x-(x-6))+1=0
We multiply parentheses
3x-(6x-(x-6))+9+1=0
We calculate terms in parentheses: -(6x-(x-6)), so:We add all the numbers together, and all the variables
6x-(x-6)
We get rid of parentheses
6x-x+6
We add all the numbers together, and all the variables
5x+6
Back to the equation:
-(5x+6)
3x-(5x+6)+10=0
We get rid of parentheses
3x-5x-6+10=0
We add all the numbers together, and all the variables
-2x+4=0
We move all terms containing x to the left, all other terms to the right
-2x=-4
x=-4/-2
x=+2
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